To return a node, list it in the return statemenet.

Query

start n=(2) return n

The node.

Result

 +--------------------+
 | n                  |
 +--------------------+
 | Node[2]{name->"B"} |
 +--------------------+
 1 rows, 0 ms

To return a relationship, just include it in the return list.

Query

start n=(1) match (n)-[r:KNOWS]->(c) return r

The relationship.

Result

 +--------------+
 | r            |
 +--------------+
 | :KNOWS[0] {} |
 +--------------+
 1 rows, 1 ms

When you want to output the relationship type, and not the whole relationship, you can use ~TYPE.

Query

start n=(1) match (n)-[r]->() return r~TYPE

The relationship type of r.

Result

 +--------+
 | r~TYPE |
 +--------+
 | KNOWS  |
 | BLOCKS |
 +--------+
 2 rows, 1 ms

To return a property, use the dot separator, like this:

Query

start n=(1) return n.name

The the value of the property name.

Result

 +--------+
 | n.name |
 +--------+
 | A      |
 +--------+
 1 rows, 0 ms

To introduce a placeholder that is made up of characters that are outside of the english alphabet, you can use the ` to enclose the identifier, like this:

Query

start `This isn't a common identifier`=(1)
return `This isn't a common identifier`.`<<!!__??>>`

The node indexed with name "A" is returned

Result

 +-------------------------------------------+
 | This isn't a common identifier.<<!!__??>> |
 +-------------------------------------------+
 | Yes!                                      |
 +-------------------------------------------+
 1 rows, 0 ms

If a property might or might not be there, you can select it optionally by adding a questionmark to the identifier, like this:

Query

start n=(1, 2) return n.age?

The age when the node has that property, or null if the property is not there.

Result

 +--------+
 | n.age  |
 +--------+
 | 55     |
 | <null> |
 +--------+
 2 rows, 1 ms